WebDec 10, 2024 · #ReachFast#reachfastsolution#reach#reachfastsolutioninjava#GoodInvestmentorNot#goodinvestment#good#goodinvestmentornotinjava#codechef#codechefsolution#todayc... WebReach on Time. Difficulty Rating: 279. Expand. Prev Next. Statement Hints Submissions Solution. Text & Video Solution: Content Restricted. Access text & video solutions curated …
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WebNov 9, 2024 · Tom And Jerry 1 (TANDJ1) CodeChef Solution Problem There is a grid of size 10^5 \times 10^5 105 ×105, covered completely in railway tracks. Tom is riding in a train, currently in cell (a, b) (a,b), and Jerry is tied up in a different cell (c, d) (c,d), unable to move. The train has no breaks. WebTime Limit Exceeded Your program was compiled successfully, but it didn't stop before time limit. Try optimizing your approach. Wrong Answer Your program compiled and ran … portlandia ghosts of bad advice
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WebFeb 27, 2024 · Codechef Solutions — Beginner Level (Python) PART 4 Car or Bus Problem Code: TRAVELFAST Chef wants to reach home as soon as possible. He has two options: Travel with his BIKE which takes XX... WebJun 23, 2024 · Advertising Reach developers & technologists worldwide; About the company; ... Outside of the CodeChef environment, you can test and debug your work. You chose to tackle the problem, and equally it is up to you to solve the challenge. You especially should go over your code looking for array bounds abuse and uninitialsed variables which … WebMay 3, 2010 · 2 Answers Sorted by: 1 Assuming that B and M are different from 0, this algorithm corresponds to one version of the Euclidean algorithm. Therefore, you can simply: std::cout << 2 * std::gcd (B, M) << "\n"; If at least one of the quantity is equal to 0, then just print B + M. Share Improve this answer Follow answered Feb 7, 2024 at 17:14 Damien option rfc1918_filter 1